How many moles of nitrogen, n, are in 82.0 g of nitrous oxide, n2o?

Answer : The number of moles of nitrogen present in nitrous oxide are 3.72 moles.

Explanation : Given,

Mass of  = 82.0 g

Molar mass of = 44 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of nitrogen in nitrous oxide.

In nitrous oxide , there are 2 moles of nitrogen and 1 mole of oxygen.

As, 1 moles of contains 2 moles of nitrogen

So, 1.86 moles of contains of nitrogen

Therefore, the number of moles of nitrogen present in nitrous oxide are 3.72 moles.

= 3.064 g/L

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Number of moles is 1 since one mole has a mass equivalent to the molar mass.

Therefore; We can find the volume and thus get the density.

V = nRT/P

   = (1 × 0.08206 × 498 )/ 0.939

   = 43.52 L

But; density = mass/volume

Therefore;

Density = 133.34 / 43.52

             = 3.064 g/L