How many moles of no2 will form when 3.3 moles of cu are reacted with excess hno3?

6.6 moles.

Explanation:

It is a stichiometric oriented problem.We need to write the balanced chemical equation of the reaction:

Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O.

It is clear that 1.0 mole of Cu reacts with 4.0 moles of 4HNO₃ to produce 1.0 mole of Cu(NO₃)₂, 2.0 moles of NO₂, and 2.0 moles of water.

Now, using cross multiplication:

1.0 mole of Cu produces → 2.0 moles of NO₂, from the stichiometry,

∴ 3.3 moles of Cu produces → ??? moles of NO₂.

∴ the number of moles of NO₂ will form when 3.3 moles of Cu are reacted with excess HNO₃ is = (3.3 moles of Cu) (2.0 moles of NO₂) / (1.0 mole of Cu ) = 6.6 moles.

4 moles

Explanation:

From the balanced chemical equation, it can be seen that 6 moles of lithium react with 1 mole of nitrogen to give 2 moles of lithium nitride.

Now as nitrogen is in excess, lithium is the limiting reagent as it limits the formation of products.

As 6 moles of lithium produce 2 moles of lithium nitride.

12 moles of lithium will produce= of lithium nitride.