How much energy is required to melt 13.00 kg of ice at 273 k? the specific latent heat of fusion of ice is 3.36 x 10^5 j kg-1.
a. 1.19 x 10^9 j
b. 2.58 x 10^4 j
c. 4.37 x 10^6 j
d. 1174.83 j

You use the information given by the question about latent heat of fusion of ice and construct the following reasoning:

if you need              3.36 × 10⁵ J to melt 1 kg of ice

then you need                      X  J to melt 13 kg of ice

X = (13 × 3.36 × 10⁵)/1 = 43.68  × 10⁵ J = 4.368  × 10⁶ J ≈ 4.37 × 10⁶ J

Answer might be b. I think

b. 0.10 M Ob(NO3)2