Identify the spectator ions in this reaction. check all that apply. 2h+ + cro4– + ba2+ + 2oh– ba2+ + cro4– + 2h2o h+ cro4– ba2+ oh– 2h2o

CrO₄⁻ and  Ba²⁺


Explanation:


1) Chemical equation given:

2H⁺ + CrO₄⁻ + Ba²⁺ + 2OH⁻ → Ba²⁺ + CrO₄⁻ + 2H₂O


2) Analysis

That is an oxidation-reduction equation (some species are been oxidized and others are being reduced).

The given equation is known as total ionic equation, because it shows all the species as ions that are part of the reaction.

2) Specator ions

Spectator ions are the ions that do not change their oxidation state and are easily identified as they are the same in the reactant and product sides.

Here the ions that are the same in the reactant and product sides are:

CrO₄⁻ and  Ba²⁺


3) Addtitional explanation.


Once you identify the spectator ions you can delete them from the equation to obtain the net ionic equation , which in this case turns to be:


2H⁺ + 2OH⁻ →  2H₂O

But this is  not part of the question; it is some context to help you  understand the use of the spectator ions concept.

The question is incomplete, the complete question is:

A 7.00 L tank at is filled with 5.43 g of sulfur hexafluoride gas and 14.2 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas. Round each of your answers to significant digits.

The mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

......(1)

For sulfur hexafluoride:

Given mass of sulfur hexafluoride = 5.43 g

Molar mass of sulfur hexafluoride = 146.06 g/mol

Putting values in equation 1, we get:

For sulfur tetrafluoride:

Given mass of sulfur tetrafluoride = 14.2 g

Molar mass of sulfur tetrafluoride = 108.07 g/mol

Putting values in equation 1, we get:

Total moles of gas in the tank = [0.0372+ 0.1314] mol = 0.1686 mol

Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:

.....(2)

where n is the number of moles

Putting values in equation 2, we get:

Hence, the mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779