hany90

hany90

16.04.2021 •

Chemistry

If 2.40 mol of carbon are exposed to 3.10 mol of steam identify the limiting reactant? How many moles of each product are formed? SHOW WORK OR NO CREDIT!!

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Ответ:

aria2289

22.05.2023

$P_1=P_2=9.86\\Q_1=Q_2=20.28\\\pi_1=\pi_2=137.09$

Explanation:

Q_1 = 40 - 3p_1 +p_2, MC_1 = 3.10

$TR_1 = P_1 \times Q_1 = 40P_1 - 3P_1^2 + P_1P_2$

$TC_1 = MC_1 \times Q_1 = 3.10 (40 - 3P_1 + P_2)$

= 124 - 9.3P_1 + 3.10P_2

$Profit, \pi_1 = TR_1 - TC_1$

= 40P_1 - 3P_2^2 + P_1P_2 - 124 + 9.3P_1 - 3.10P_2

49.3P_1 - 3.10P_2 + P_1P_2 - 3P_1^2 - 124

$\frac{d\pi}{dP_1} = 0$ when profit is maximized

= 49.3 + P_2 - 6P_1 = 0

6P_1 - P_2 = 49.3 [Response Function for firm 1] ...........(1)

again

B_2 = 40 - 3P_2 + P_1 , MC_2 = 3.10

$TR_2 = P_2 \times B_2 = 40P_2 - 3P_2^2 + P_1P_2$

$TC_2 = MC_2 \times B_2 = 3.10(40 - 3P_2 + P_1)$

= 124 - 9.3P_2 + 3.10P_1

$\pi_2 =TR_2 - TC_2 = 40P_2 - 3P_2^2 +P_1P_2 - 124 + 9.3P_2 - 3.10P_1$

= 49.3P_2 - 3.10P_1 + P_1P_2 - 3P_2^2

check additional details in the attached file

Two firms produce and sell differentiated products that are substitutes for each other. Their demand

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