If 45.0 ml of ethanol (density=0.789 g/ml) initially at 9.0 c is mixed with 45.0 ml of water (density=1.0 g/ml) initially at 28.6 c in an insulated beaker, and assuming that no heat is lost, what is the final temperature of the mixture?
i tried many times in trying to get the answer, but i keep getting it wrong. i appreciate who answers this writes it step by step. you.
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Ответ:
Answer : The final temperature of the mixture is
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
And as we know that,
Mass = Density × Volume
Thus, the formula becomes,
where,
= specific heat of ethanol =
= specific heat of water =
= mass of ethanol
= mass of water
= density of ethanol = 0.789 g/mL
= density of water = 1.0 g/mL
= volume of ethanol = 45.0 mL
= volume of water = 45.0 mL
= final temperature of mixture = ?
= initial temperature of ethanol =
= initial temperature of water =
Now put all the given values in the above formula, we get
Therefore, the final temperature of the mixture is
Ответ:
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Explanation: