If 4520 kJ of heat is needed to boil a sample of water, what is the mass of the sample of water (ΔHvaporiztion = 2260kJ/kg)?
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Ответ:
2kg
Explanation:heat gained=heat lost
mass x 2260=4520
4530÷2260
And=2kg
Ответ:
That means
x(3p) + y(2p) = 32p
2y(3p) + y(2p) = 32p
y [2(3p) + 2p] = 32 p
y [ 8p ] = 32 p
y = 4
4 x 2 = 8 ; and 32 - 8 = 24
Which means x = 8
Hope this helps