If a balloon with a volume of 10L at 500kpa is heated until the balloon has a temperature of 300°C, 750atm and now has a volume of 100mL. What was the original temperature of the balloon (in °C)

103.6°C

Explanation:

We solve this problem, with the Ideal Gases Law. We know that moles of gas are not changed through time.

P . V = n . R . T

So n (number of moles) and R (Ideal Gases constant) are the same, they are cancelled. In the two different states, we can propose:

P₁ . V₁ / T₁ = P₂ . V₂ /T₂

We need to make some conversions:

100 mL . 1 L/ 1000mL = 0.1L

500 kpa . 1atm / 101.3 kPa = 4.93 atm

300°C + 273 = 573 K

We replace data:

4.93 atm . 10L / T₂ = 750 atm . 0.1L / 573K

4.93 atm . 10L = (750 atm . 0.1L / 573K) . T₂

(4.93 atm . 10L) / (750 atm . 0.1L / 573K) → T₂

T₂ = 376.65 K

We convert K to °C →  376.65 K - 273 = 103.6 °C

def func1(x):

   return (x-32)*(5/9)

def func2(x):

   return (x/2.237)

def main():

   x = ""

   while x != "x":

       choice = input("Enter 1 to convert Fahrenheit temperature to Celsius\n"

                      "Enter 2 to convert speed from miles per hour to meters per second: ")

       if choice == "1":

           temp = input("please enter temperature in farenheit: ")

           print(func1(float(temp))," degrees celcius.")

       elif choice == "2":

           speed = input("please enter speed in miles per hour: ")

           print(func2(float(speed))," meters per second")

       else:

           print("error... enter value again...")

       x = input("enter x to exit, y to continue")

if __name__ == "__main__":

    main()

Explanation:

two function are defines func1 for converting temperature from ferenheit to celcius and func2 to convert speed from miles per hour to meters per second.