If a car produces 88 grams of co2 how many grams of o is used up in the reactionin c2h6o o2

B. (4.0 mol C2H6O) x (3/1) = 12 mol O2 

C. Supposing all the C in the CO2 came from ethanol: 
(88 g CO2) / (44.00964 g CO2/mol) x (3/2) x (31.99886 g O2/mol) = 96 g O2 

D. (125 g C2H6O) / (46.06867 g C2H6O/ mol) x (2/1) x (44.00964 g CO2/mol) = 
239 g CO2 

(125 g C2H6O) / (46.06867 g C2H6O/ mol) x (3/1) x (18.01532 g H2O/mol) =

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Explanation:

Just answered it and got it right