If the titration of a 25.0 mL sample of calcium hydroxide requires 34.45 mL of 0.100 M hydrochloric acid, what is the molarity of the base?

As a reactive, monoprotic acid, it will neutralize an equivalent amount of dilute NaOH ... Prepare about 300 ml of well-mixed 0.12 M NaOH from the available NaOH stock ... Molar mass of KHP (potassium hydrogen phthalate, KHC8H4O4) ... If the titration of a 25.0 mL sample of calcium hydroxide requires 34.45 mL of 0.100

Explanation:

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Ans: P = 22.5% and Cl = 77.5%

Given:

Total Mass of sample containing P and Cl = 50.51 g

Mass of P produced = 11.39 g

To determine:

Mass % of P and Cl

Explanation:

Mass % of a given element in a total mass is generally expressed as:

Mass % of element = [mass of element/total mass]*100

Here,

Total mass = mass of P + mass of Cl

mass of Cl = Total - mass of P = 50.51-11.39 = 39.12 g

% P = [11.39/50.51]*100 = 22.5%

%Cl = [39.12/50.51]*100 = 77.5%