If you initially have a gas at a pressure of 14kPa, volume of 20L, and a temperature at 205K and then I raise the pressure to 16 kPa, and increase the temperature to 350K, what is the new volume of gas? Choose the appropriate gas law and use a calculator to complete the problem.

V₂ = 29.88 L

Explanation:

Given data:

Initial volume = 20 L

Initial pressure = 14 KPa

Initial temperature = 205 K

Final temperature = 350 K

Final volume = ?

Final pressure = 16 KPa

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 14 KPa × 20 L × 350 K / 205 K × 16 KPa

V₂ = 98000 KPa .L. K /3280 K.KPa

V₂ = 29.88 L

The answer is B. the law of independent assortment