If you supply 3600 kj of heat, how many grams of ice at 0°c can be melted, heated to its boiling point? (make m your x in equations) (figure out which q you need)
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Ответ:
=1.36kg
Explanation:
First heat is absorbed to melt the ice- latent heat of fusion of ice then heat is absorbed to raise the temperature to 373K
The specific heat capacity of water is 4.187kJ/kg/K while the latent heat of fusion of ice is 2230kJ/kg/K.
Letting the mass of the ice to be =x
x×2230kJ/kg/K + x×4.187kJ/kg/K×100K= 3600kJ
2230x+418.7x=3600
2647.8x=3600
x=1.36 kg
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