alejandraluna95

01.05.2021 •

Chemistry

If you were to go into your kitchen and stir milk into vanilla pudding mix, or cream into coffee, you would be making a. chemical compound
b. homogeneous mixtures
c. heterogeneous mixtures
d. combinations of elements

Solved

Show answers

Ответ:

rwbrayan8727

08.07.2020

Chemistry

$Cu+Au^{3+}\rightarrow Cu^{2+}+Au$

Explanation: when E^0 = +ve, reaction is spontaneous

E^0 = -ve, reaction is non spontaneous

E^0 = 0, reaction is in equilibrium

1. $Ni+Zn^{2+}\rightarrow Ni^{2+}+Zn$

Here Ni undergoes oxidation by loss of electrons, thus act as anode. zinc undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both E^0 are standard reduction potentials.

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0_{[Ni^{2+}/Ni]}= -0.26V$

$E^0=E^0_{[Zn^{2+}/Zn]}- E^0_{[Ni^{2+}/Ni]}$

E^0=-0.76V- (-0.26V)=-0.50V

As the standard emf comes to be negative, the reaction is non spontaneous.

2) $Mg+Li^{+}\rightarrow Mg^{2+}+Li$

Here Mg undergoes oxidation by loss of electrons, thus act as anode. Lithium undergoes reduction by gain of electrons and thus act as cathode.

$E^0_{[Mg^{2+}/Mg]}= -2.37V$

$E^0_{[Li^{+}/Li]}= -3.05V$

$E^0=E^0_{[Li^{+}/Li]}- E^0_{[Mg^{2+}/Mg]}$

E^0=-3.05- (-2.37V)=-0.68V

As the standard emf comes to be negative, the reaction is non spontaneous.

3) $Cu+Au^{3+}\rightarrow Cu^{2+}+Au$

Here Cu undergoes oxidation by loss of electrons, thus act as anode. Gold undergoes reduction by gain of electrons and thus act as cathode.

$E^0_{[Au^{3+}/Au]}= +1.40V$

$E^0_{[Cu^{2+}/Cu]}= 0.34V$

$E^0=E^0_{[Au^{3+}/Au]}- E^0_{[Cu^{2+}/Cu]}$

E^0=1.40- (+0.34V)=1.06V

As the standard emf comes to be positive, the reaction is spontaneous.

4) $Zn+Ca^{2+}\rightarrow Zn^{2+}+Ca$

Here Zn undergoes oxidation by loss of electrons, thus act as anode. Calcium undergoes reduction by gain of electrons and thus act as cathode.

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0_{[Ca^{2+}/Ca]}=-2.87V$

$E^0=E^0_{[Ca^{2+}/Ca}- E^0_{[Zn^{2+}/Zn]}$

E^0=-2.87V- (-0.76V)=-2.11V

As the standard emf comes to be negative, the reaction is non spontaneous.

0,0(0 оценок)

Ask your question to the AI advisor

Ai-bot is an expert in any field and is the perfect companion for reliable and useful answers and advice on a variety of topics, including science, history, technology, art, sports, health, culture and more.

Ask your question

More tips

Answers on questions: Chemistry

Ask an AI advisor a question

I want advice

If you were to go into your kitchen and stir milk into vanilla pudding mix, or cream into coffee, you would be making a. chemical compound b. homogeneous mixtures c. heterogeneous mixtures d. combinations of elements

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question

If you were to go into your kitchen and stir milk into vanilla pudding mix, or cream into coffee, you would be making a. chemical compound
b. homogeneous mixtures
c. heterogeneous mixtures
d. combinations of elements