Ihad 10 molecules of ag and an unlimited supply of h2s. how many molecules of ag2s could i produce?

5.12 molecules of Ag₂S could be produced from 10 molecules of silver.

Explanation:

Given data:

Molecules of Ag = 10 molecules

Molecules of Ag₂S = ?

Solution:

First of all we will convert the number of molecules into gram.

10/ 6.022 ×10²³ = 1.7 × 10⁻²³ mol

Mass of Ag:

Number of moles = mass/ molar mass

Mass = Number of moles × molar mass

Mass = 1.7 × 10⁻²³ mol × 107.9 g/mol

Mass = 183.43 × 10⁻²³ g

Chemical equation:

2Ag  + H₂S  →  Ag₂S + H₂

Now we will compare the moles of silver with Ag₂S from balanced chemical equation.

         Ag           :         Ag₂S

          2             :          1

     1.7 × 10⁻²³    :          1/2 ×1.7 × 10⁻²³  = 0.85 × 10⁻²³ mol

Molecules of Ag₂S:

0.85 × 10⁻²³ × 6.022 ×10²³ = 5.12 molecules

The balanced equation is .

Explanation:

The given reaction equation is as follows.

Number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply Li by 2 and by 2 on reactant side. Also, multiply by 2 on product side.

Hence, the equation can be rewritten as follows.

Now, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is .