Ihave a 270 g cup of coffee at 94.1 degrees celsius. assume that the specific heat of coffee is the same as pure water, 4.18 j/gc. i have a silver spoon at 26.8 degrees celsius. the heat capacity of the silver spoon is 61.2 j/c. when i place the cool spoon in the hot coffee the system will come to thermal equilibrium. assume that the only heat flow is between the spoon and the coffee. what will the temperature of the coffee be at thermal equilibrium?
show your work!
Solved
Show answers
More tips
- C Computers and Internet How to insert videos into LiveJournal?...
- C Computers and Internet How Much Does an iPhone Cost in America?...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- H Health and Medicine Headache: A Comprehensive Guide to Treatment...
- C Computers and Internet How to Properly Order Clothing from International Online Stores...
- A Auto and Moto Mastering One-Movement Parking: All You Need to Know...
- D Dating, Love, Relationships How Long Can Love Last?...
- S Society and Politics Is It Fact or Fiction? Let s Talk About Anton Chekhov s Pseudonym...
- F Food and Cooking How to Find Your Zip Code?...
- S Style and Beauty How to choose the best mascara for your eyelashes...
Answers on questions: Chemistry
- C Chemistry Draw a stepwise mechanism for the chlorination of 2−phenylethanol with thionyl chloride in pyridine:...
- M Mathematics Find slope (3,-4),(-2,8)...
- M Mathematics the sum of three numbers is 90. the third number is 4 times the first. the second number is 6 less than the first. what are the numbers...
- B Biology Emergency medical care for internal bleeding includes:...
- M Mathematics There are 2 pies on the shelf. Each shelf is cut into eighths. How many pieces of pie are there?...
Ответ:
90.64 degrees
Explanation:
Lets list out the parameters given in the question.
Mass of Cup = 270g
Temp. of cup = 94.1C
Specific heat capacity of C = 4.18J/gC
Temp. of Silver spoon = 26.8C
heat capacity of the silver spoon = 61.2 J/C
The fact that thermal equilibrium was mentioned simply means that;
Heat Lost by coffee= Heat gained by spoon
The relationship between the parameters mentioned is given as;
Q = m* c * dT
Where;
m is the mass, c is the specific heat capacity and dT is the "change" in temperature.
Assume the final temperature of the whole system is "x". They would both have the same final temperature since they are in thermal equilibrium.
Heat lost by coffee = 270 * 4.18 * (94.1 - x)
(94.1 -x) because coffee will loose heat, hence temperature of coffee will fall.
Heat gained by spoon = c *dT = 61.2 * (x - 26.8).
dT = Final Temp. - Initial Temp.
dT = x - 26.8
Heat lost = Heat gained :
270 * 4.18 * (94.1 - x) = 61.2 * (x - 26.8),
1128.6 (94.1 - x) = 61.2 (x- 26.8)
18.44 ( 94.1 - x) = x - 26.8
1735.2 - 18.44 x = x - 26.8
1735.2 + 26.8 = x + 18.44 x
1762 = 19.44 x
x = 90.64 degrees
Ответ:
1 is B
Explanation:
Ice is crystalline so when water drops below freezing it forms crystals, I don't know the rest.