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2020IRodriguez385
03.03.2020 •
Chemistry
In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced by a water molecule, yielding the pinkish-orange complex ion : Co(NH3)5(H2O)3+
Co(NH3)5Br2+Purple(aq)+H2O(l)? Co(NH3)5(H2O)3+Pinkish?orange(aq)+Br?(aq...
The reaction is first order in Co(NH3)5Br2+, the rate constant at 25 ?C is 6.3�10?6 s?1, and the initial concentration of Co(NH3)5Br2+ is 0.100 M.
A; What is its molarity after a reaction time of 19.0h ?
B; How many hours are required for 69% of the Co(NH3)5Br2+ to react?
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Ответ:
A) 0.065 M is its molarity after a reaction time of 19.0 hour.
B) In 52 hours
will react 69% of its initial concentration.
Explanation:
The reaction is first order in
:
Initial concentration of
= ![[A_o]=0.100 M](/tpl/images/0532/7758/bacc4.png)
a) Final concentration of
after 19.0 hours= ![[A]](/tpl/images/0532/7758/6aa06.png)
t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)
Rate constant of the reaction = k =![6.3\times 10^{-6} s^{-1}](/tpl/images/0532/7758/3b77a.png)
The integrated law of first order kinetic is given as:
0.065 M is its molarity after a reaction time of 19.0 h.
b)
Initial concentration of
= ![[A_o]=x](/tpl/images/0532/7758/aecde.png)
Final concentration of
after t = ![[A]=(100\%-69\%) x=31\%x=0.31x](/tpl/images/0532/7758/34138.png)
Rate constant of the reaction = k =![6.3\times 10^{-6} s^{-1}](/tpl/images/0532/7758/3b77a.png)
The integrated law of first order kinetic is given as:
t = 185,902.06 s =
≈ 52 hours
In 52 hours
will react 69% of its initial concentration.
Ответ:
Explanation:
edg 2021