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87haymaker
30.11.2019 •
Chemistry
In the electrochemical cell using the redox reaction below, the anode half reaction is sn4+ (aq) + fe (s) → sn2+ (aq) + fe2+ (aq) in the electrochemical cell using the redox reaction below, the anode half reaction is (aq) + (s) (aq) + (aq) fe→fe2++2e− sn4+→sn2++2e− fe+2e−→fe2+ sn4++2e−→sn2+ fe+2e−→sn2+ request answer
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Ответ:
The anode half reaction is :![Fe(s)\rightarrow Fe^{2+}(aq.)+2e^{-}](/tpl/images/0397/1854/cd672.png)
Explanation:
In electrochemical cell, oxidation occurs in anode and reduction occurs in cathode.
In oxidation, electrons are being released by a species. In reduction, electrons are being consumed by a species.
We can split the given cell reaction into two half-cell reaction such as-
Oxidation (anode):![Fe(s)\rightarrow Fe^{2+}(aq.)+2e^{-}](/tpl/images/0397/1854/cd672.png)
Reduction (cathode):![Sn^{4+}(aq.)+2e^{-}\rightarrow Sn^{2+}(aq.)](/tpl/images/0397/1854/07d2f.png)
------------------------------------------------------------------------------------------------------------
overall:![Fe(s)+Sn^{4+}(aq.)\rightarrow Fe^{2+}(aq.)+Sn^{2+}(aq.)](/tpl/images/0397/1854/b239a.png)
So the anode half reaction is :![Fe(s)\rightarrow Fe^{2+}(aq.)+2e^{-}](/tpl/images/0397/1854/cd672.png)
Ответ:
This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system. In other words, in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.
Explanation: