Chemistry: In the following reaction, how many grams of nitroglycerin c3h5(no3)3 will decompose to give 25 grams of co2? 4c3h5(no3)3(l) 12co2(g) + 6n2(g) + 10h2o(g) + o2(g) the molar mass of nitroglycerin is 227.0995 grams and that of carbon dioxide is 44.01 grams.

In the following reaction, how many grams of nitroglycerin

alejandramirand9836

12.01.2022

4C₃H₅(NO₃)₃ $_{(l)}$ ------> 12CO₂ $_{(g)}$ + 6N₂ $_{(g)}$ + 10H₂O $_{(g)}$ + O₂ $_{(g)}$

mol of CO₂ = $\frac{mass}{molar mass}$

= $\frac{25g}{44.01 g/mol}$

mol ratio of CO₂ : C₃H₅(NO₃)₃

12 : 4

∴ if mole of CO₂ = 0.568 mol

then " " C₃H₅(NO₃)₃ = $\frac{0.568 mol}{12} * 4$

= 0.189 mol

∴ mass of nitroglycerin = mole * Mr

= 0.189 mol * 227.0995 g / mol

= 43.00 g

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