In the following reaction, what is the limiting reactant, and how many molecules of water will I create?
2H2 + O2 --> 2H2O
I have 11 molecules of Hydrogen and 8 molecules of Oxygen.
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Ответ:
T = 3006.976 K
Explanation:
∴ ΔH° = 125 KJ/mol ( 800K - 1500K)
∴ ΔG° = 25 KJ/mol (1150 K)
⇒ T = ? ∴ K > 1
In the equilibrium:
K = e∧(ΔG°/RT)∴ K > 1
If ΔG°/RT = 1
⇒ e∧(1) = 2.72 > 1
∴ ΔG°/RT = 1
⇒ T = ΔG°/R = (25 KJ/mol)/(8.314 E-3 KJ/mol.K)
⇒ T = 3006.976 K
verifying:
K = e∧(ΔG°/RT)⇒ K = e∧(25/((8.314 E-3)(3006.976)))
⇒ K = 1.000000061 > 1