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gustinya000
02.07.2019 •
Chemistry
In the reaction fecl2 + 2naoh -> fe(oh)2(s) + 2nacl, if 6 moles of fecl2 are added to 6 moles of na0h, how many moles of naoh would be used up in the reaction? - apex a. 3 b. 6 c. 2 d. 1
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Ответ:
Answer : The correct option is, (B) 6 mole
Explanation :
Given moles of
= 6 moles
Given moles of
= 6 moles
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the given balanced reaction, we conclude that
As, 1 moles of
react with 2 moles of ![NaOH](/tpl/images/0042/3004/60f59.png)
So, 6 moles of
react with
moles of ![NaOH](/tpl/images/0042/3004/60f59.png)
From this we conclude that,
is an excess reagent and
is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.
Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH
The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles
Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles
Ответ:
Lithium ( 3),Calcium (20),Copper (29),Strontium (38),Potassium (19),Sodium (11)
Explanation: