Kc=kp
(RT)n
Kc = 1.92*10-4 Nm-2
18:314mol'k 'X314
4k)

Oxygen.

Explanation:

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In this case, since the ideal gas equation allows us to compute the moles of oxygen in 5.60 L at STP (1 atm and 273.15 K) as shown below:

Next, given the molar mass of carbon dioxide (44.01 g/mol) we compute the moles in 10.0g of this gas via:

Thus, since oxygen has the greatest number of moles, we immediately infer it also has the greatest number of molecules based on the Avogadro's number.

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