zanestone12
19.02.2020 •
Chemistry
Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit cell and (b) the radius of a Mo atom.
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Ответ:
For a: The edge length of the unit cell is 314 pm
For b: The radius of the molybdenum atom is 135.9 pm
Explanation:
For a:To calculate the edge length for given density of metal, we use the equation:
where,
= density =
Z = number of atom in unit cell = 2 (BCC)
M = atomic mass of metal (molybdenum) = 95.94 g/mol
= Avogadro's number =
a = edge length of unit cell =?
Putting values in above equation, we get:
Conversion factor used:
Hence, the edge length of the unit cell is 314 pm
For b:To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:
where,
R = radius of the lattice = ?
a = edge length = 314 pm
Putting values in above equation, we get:
Hence, the radius of the molybdenum atom is 135.9 pm
Ответ:
Answer is: sulfur, arsenic, selenium, silicon and antimony.
1) Sulfur (S) can form, for example, sulfuric acid (H₂SO₄) or acidic oxide, sulfur(VI) oxide (SO₃).
2) Arsenic (As) can form arsenous acid (H₃AsO₃).
3) Selenium (Se) can form selenic acid (H₂SeO₄).
4) Silicon (Si) can form orthosilicic acid Si(OH)₄ and metasilicic acid SiO(OH)₂.
5) Antimony (Sb) can form antimonic acid, as the hydrate HSb(OH)₆.