Mr. Whiteman has two stock solutions of sulfuric acid (H2SO4) in the supply closet: 12.1 M and 6.0 M. If he wants to make 10.0 mL of a 1.0 M solution, which stock solution makes more sense to use? Justify with two calculations.

12.1-M requires less volume of stock solution.

Explanation:

Hello there!

In this case, according to the foundations of dilution processes, it turns out convenient to remember that the moles of the solute before and after the dilution remains the same; for that reason we use the following equation:

Relating the initial and final molarities and volumes. Now, it is seen that V2 is 10.0 mL and M2 is 1.0 M, which means that if we solve for V1 for 12.1 M and 6.0 M, we obtain the following volumes:

Therefore, since the 12.1-M solution requires less volume of stock solution, it makes sense to use this one as the initial solution.

Best regards!

The First answer is

VWXZ+VWXY+WYZ+VXY+VWZ+XYZ

The second possible answer is:

VWXZ+VWYZ+WYZ+VXY+VWZ+XYZ

Step-by-step explanation:

First we draw the k-maps for the function . There are two k-maps, one with V as zero while the other is V as 1. Then we combine the entries in power of 2. Remember that the function is given in maxterms form.Max-terms are those whose value is 0. So all the values other than max-values are either 1 or don't care. So we will keep these terms 0 and other as 1. The k-maps are attached in the files below. The essential prime implicants are those which are repeated in all the possible solutions.In this case Essential prime implicants are :

VWXZ+WYZ+VXY+VWZ+XYZ

http://www.32x8.com/sop5A-B-C-D-Em_4-5-7-8-10-14-15-16-17-18-21-22-23-31d_1-2-12-13option-0899788976571894282724?fbclid=IwAR2BaNgaMe0FXK1AEcwzLb1tkw5Oo-DIn-w0QNxE6ck9nYOSS1GnGtWC4SU