alcott1110
31.08.2020 •
Chemistry
Nitrogen dioxide undergoes thermal decomposition according to the second-order reaction 2 NO2(g) 2 NO(g) + O2(g). When 0.500 M NO2 is allowed to react for 90.0 seconds, its concentration falls to 0.0196 M. What is the half-life of the reaction when [NO2]0 = 0.500 M?
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Ответ:
half-life is 3.67s
Explanation:
The general law of the second-order reaction is:
As after 90.0s, the concentration of NO2 decreases from 0.500M to 0.0196M:
49.02M⁻¹ = K*90.0s
0.5447M⁻¹s⁻¹ = K
Now, half-life, t1/2 is:
Half-life is:
t(1/2) = 1 / (0.5447M⁻¹s⁻¹*0.500M)
half-life is 3.67sОтвет:
power=work done / time taken