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how many joules are needed to heat 20g of Cu from 10 to 50 degrees C?

q=309.6 J

Explanation:

Here we'll be using the formula of specific heat capacity: Q=mcΔT

Q= heat (joules)

m=mass (g)

c=specific heat capacity

ΔT= change in temperature > Final temp. - initial temp.

Let's plug in what we know and solve for q=heat.

q=(20)(0.387)(50-10)

q=(20)(0.387)(40)

q=309.6 joules

Depending on your teacher and the problem, they might want you to keep the temperature in C. Mine wanted them all in Kelvin, so if we were to convert it to Kelvin it would be:

273 + 40= 313 K

q=(20)(0.387)(313)

q=2422.6 J

89°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(1.25 atm)(450 mL)/(65°C) = (0.89 atm)(865 mL)/T₂

8.653846154 = 769.85/T₂

T₂ = 769.85/8.653846154

T₂ = 88.96044444 = 89°C