Chemistry: On a hot day, a 15.0 kg window increased from 20.0 degrees C to 26.7 degrees C. How much heat energy did the glass window absorb? (specific heat of glass = 0.840 J/gC)

On a hot day, a 15.0 kg window increased from - id15020013187609, kutemigos9211

dee21099

11.06.2021

The heat energy absorbed by glass window is 84420 J.

Explanation:

Given: Mass = 15 kg (1 kg = 1000 g) = 15000 g

Initial temperature = $20^{o}C$

Final temperature = $26.7^{o}C$

Specific heat capacity = $0.840 J/g^{o}C$

Formula used is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass of substance

C = specific heat capacity

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\ q = 15000 g \times 0.840 J/g^{o}C \times (26.7 - 20)^{o}C\\q = 84420 J$

Thus, we can conclude that the heat energy absorbed by glass window is 84420 J.

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keke6361

19.02.2021

the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.

Explanation:

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