Oxygen at 150 k and 41.64 atm has a tabulated specific volume of 4.684 cm3/g and a specific internal energy of 1706 j/mol. calculate the specific enthalpy of o2 in this state.

The total energy in a system due to the temperature and pressure per unit mass in that system is known as specific enthalpy. It is used in thermodynamic equations when one desires to know the energy for a given single unit mass of a component.  

Specific enthalpy is calculated by the equation:  

H = U + PV

in the given case, Specific volume = 4.684 cm³/g = 149.888 cm³/g moles = 149.888 × 10⁻³ J/g moles

Specific internal energy (U) is 1706 J/mol and pressure is 41.64.  

H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules  

= 2428 joules / mole

your first question huh?

Explanation: