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09.03.2023

The empirical formula : C₁₂H₁₇N₂O₄P

Further explanation

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

Determine the mass ratio of the constituent elements of the compound. Determine the mole ratio by by dividing the percentage by the atomic mass C

$\tt \dfrac{50.7}{12}=4.225$

$\tt \dfrac{6.03}{1}=6.03$

$\tt \dfrac{9.86}{14}=0.704$

$\tt \dfrac{22.51}{16}=1.407$

$\tt \dfrac{10.9}{31}=0.352$

Divide by the smallest mole ratio(0.352)

C : H : N : O : P

$\tt C\rightarrow \dfrac{4.225}{0.352}=12$

$\tt H\rightarrow \dfrac{6.03}{0.352}=17$

$\tt N\rightarrow \dfrac{0.704}{0.352}=2$

$\tt O\rightarrow \dfrac{1.407}{0.352}=4$

$\tt P\rightarrow \dfrac{0.352}{0.352}=1$

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