ijohnson020702
10.12.2020 •
Chemistry
Please answer
Question 4(5 points)
If 2.0 moles of water is cooled from 101 degree C steam to -1.0 degree Cice, what is the total energy lost?
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Ответ:
Q = -15363.65 J
Explanation:
Given data:
Number of moles of water = 2.0 mol
Initial temperature = 101°C
Final temperature = -1.0°C
Total energy lost = ?
Solution:
Mass of water:
Mass = number of moles × molar mass
Mass = 2 mol × 18 g/mol
Mass = 36 g
Heat lost:
specific heat capacity of water is 4.184 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = -1.0°C - 101°C
ΔT = -102°C
Q = 36 g × 4.184 J/g.°C × -102°C
Q = -15363.65 J
Negative sign show heat is released.
Ответ:
answer:
im sorry i would hellp you but i dont know the anser
explanation: