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The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)

13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

Then mol iodine (MW=126.9045 g/mol) :

mol ratio of Cobalt and Iodine in the compound :

Option A.

Explanation:

To know which structure is correct, let us name both compound.

In naming the above organic compound, the following must be observed:

1. Locate the functional group. In this case it alkene since it has carbon to carbon double bond (C=C).

2. Locate the longest continuous carbon chain. In this case the compound is a cyclic compound with 6 carbon i.e cyclohexene.

3. Locate the substituents attached to the compound. In this case, bromine (bromo) and chlorine (chloro) are the substituents attached.

4. Locate the position of the substituents and name alphabetically counting from the double bond. In this case, bromo comes before chloro

5. Combine the above to get the name.

For option A, the name is:

4–bromo–5–chlorocyclohexene.

For option B, the name is:

3–bromo–4–chlorocyclohexene.

We can see that Option A gives the correct structure of the compound.