ziyonsolange
13.01.2021 •
Chemistry
Pls helpp An unknown substance with a mass of 23.5 grams absorbs 419.7 J while undergoing a temperature increase of 76.0°C. What is the specific heat of the substance?
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Ответ:
The specific heat of the substance : c = 0.235 J/g °C
Further explanationGiven
Heat absorbed by substance = 419.7 J
m = mass = 23.5 g
Δt = Temperature difference : 76 °C
Required
The specific heat
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
419.7 = 23.5 x c x 76
c = 419.7 : (23.5 x 76)
c = 0.235 J/g °C
Ответ:
No
Explanation: