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dewayne5599
07.03.2020 •
Chemistry
Potassium nitrate has a lattice energy of -163.8 kcal/mol and a heat of hydration of -155.5 kcal /mol. How much potassium nitrate has to dissolve in water, at room temperature, to absorb 1.00 x 102 kJ of heat
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Ответ:
291.07 g potassium nitrate has to dissolve in water, at room temperature, to absorb 1.00 x 102 kJ of heat
Explanation:
Given that,
Lattice energy of Potassium nitrate (KNO3) = -163.8 kcal/mol
Heat of hydration of KNO3 = -155.5 kcal/mol
Heat to absorb by KNO3 = 100kJ
Mass of KNO3 to dissolve in water = ?
Solution:
Heat of solution = Hydration energy - Lattice energy
= -155.5 -(-163.8)
= 8.3 kcal/mol
since,
1 kcal/mol = 4.184 kJ/mole
Therefore,
= 4.184 kJ/mol x 8.3 kcal/mol
= 34.73 kJ/mol
Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved in water.
For 100 kJ of heat would be
= 100/34.73
= 2.879 moles of KNO3
Molar mass of KNO3 = 101.1 g/mole
Mass of KNO3 = Molar mass x moles
= 101.1 g/mole x 2.879
= 291.07 g
= 0.291 kg
291.07 g potassium nitrate has to dissolve in water, at room temperature, to absorb 1.00 x 102 kJ of heat
Ответ:
Law of Inertia.
Explanation: