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angellll4455
04.11.2019 •
Chemistry
Propane (c3h8) reacts with oxygen in the ir to produce carbon dioxide and water. in particular experiment, 38.0 grams of carbon dioxide are produced from the reaction of 22.05 grams of propane with excess oxygen. whats is the porcent yield
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Ответ:
Percentage yield = 57.57%
Explanation:
Given data:
Actual yield of carbondioxide = 38.0 g
Mass of propane = 22.05 g
Percentage yield = ?
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Number of moles of propane:
Number of moles of propane = mass / molar mass
Number of moles of propane = 22.05 g/ 44 g/mol
Number of moles of propane = 0.5 mol
Now we compare the moles of carbon dioxide with moles of propane.
C₃H₈ : CO₂
1 : 3
0.5 : 3×0.5 = 1.5 mol
Mass of carbondioxide:
Mass of carbondioxide = moles × molar mass
Mass of carbondioxide = 1.5 mol × 44 g/mol
Mass of carbondioxide = 66 g
Percentage yield:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 38 g/ 66 g × 100
Percentage yield = 57.57%
Ответ:
polar-over high altitudes
Maritime- over water
Tropical- over lower altitudes
Continental-over land
Explanation: