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marvinc5603
29.08.2020 •
Chemistry
Prospectors are considering searching for gold on a plot of land that contains 2.45 g of gold per bucket of soil. If the volume of the bucket is 5.25L, how many grams of gold are there likely to be in 1.0 cubic feet of soil
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Ответ:
13.2 g of gold
Explanation:
We'll begin by converting 5.25 L to ft³.
This can be obtained as follow:
Recall:
1 L = 0.0353 ft³
Therefore,
5.25 L = 5.25 × 0.0353
5.25 L = 1.85×10¯¹ ft³
From the question given above,
2.45 g of gold is present in 5.25 L ( i.e 1.85×10¯¹ ft³) of soil.
Therefore, Xg of gold will be present in 1 ft³ of soil i.e
Xg of gold = 2.45/1.85×10¯¹
Xg of gold = 13.2 g
Therefore, 13.2 g of gold is present in 1 ft³ of the soil.
Ответ: