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21.04.2020 •
Chemistry
Since this reaction takes place in acidic solution, H2O(l) and H+(aq) will be involved in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: SO42−(aq)+Sn2+(aq)+ –––→H2SO3(aq)+Sn4+(aq)+ ––– Part A What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(l) and H+(aq) in the appropriate blanks. Your answer should have six terms.
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Ответ:
The balanced equation is given below:
SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)
The coefficients of the reactants are: 1, 1, 4
The coefficients of the products are: 1, 1, 1
Explanation:
Step 1:
The equation for the reaction. This is given below:
SO4^2−(aq)+ Sn^2+(aq) + –––→ H2SO3(aq)+ Sn^4+(aq) + –––
Step 2:
Inclusion of H+ and H2O into the equation. This is illustrated below:
SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)
Step 3:
Balancing the equation.
SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)
The above equation can be balanced as follow:
There are total 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H^+ as shown below:
SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)
Now the equation is balanced.
The coefficients of the reactants are: 1, 1, 4
The coefficients of the products are: 1, 1, 1
Ответ: