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16.03.2020 •
Chemistry
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO 3 ( s ) . The equation for the reaction is 2 KClO 3 ⟶ 2 KCl + 3 O 2 Calculate how many grams of O 2 ( g ) can be produced from heating 82.4 g KClO 3 ( s ) .
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Ответ:
Mass of produced = 32 g
Explanation:
Calculation of the moles of as:-
Mass = 82.4 g
Molar mass of = 122.55 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the reaction shown below:-
2 moles of potassium chlorate on reaction forms 3 moles of oxygen gas
So,
0.67237 moles of potassium chlorate on reaction forms moles of oxygen gas
Moles of oxygen gas = 1 mole
Molar mass of oxygen gas = 32 g/mol
Mass of produced = 32 g
Ответ: