Some pure calcium carbonate Let's make to react completely When 100cm3 Hydrochloric acid of unknown concentration. 120cm3 of carbon dioxide was formed at Room temperature. calculate the number of moles of carbon dioxide formed at room temperature

[A] = 0.39mg

Explanation:

The radioactive decay of an atom follows the equation:

Ln[A] = -kt + ln[A]₀

Where [A] is actual amount of isotope after time t; k is decay constant and [A]₀ initial amount of isotope

Also, we can write k in therms of half-life:

k = ln2 / Half-life

Solving for k:

k = ln2 / 14.3days

k = 0.04847days⁻¹

Solving in the equation for [A]:

Ln[A] = -0.04847days⁻¹*57.2days + ln[6.3mg]

ln[A] = -0.93193