Stoichiometry chem problem

The formula for molality---> m = moles solute/ Kg of solvent

the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

1) let's convert the grams of NH₃ to moles using the molar mass

molar mass of NH₃= 14.0 + (3 x 1.01)= 17.03 g/ mol

30.0 g (1 mol/ 17.03 g)= 1.76 mol NH₃

2) let's convert the grams of water into kilograms (just divide by 1000)

70.0g= 0.0700 kg

3) let's plug in the values into the molality formula

molality= mol/ Kg---> 1.76 mol/ 0.070 kg= 25.1 m