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4.00 x 10^23 molecules of h3po4 have an approximate mass of
a. 8g.
b. 65g.
c. 147 g.
d. 663g.
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Ответ:
atomic mass (H)=1 amu
atomic mass (P)=31 amu
atomic mass (O)=16 amu
molecular weight (H₃PO₄)=3(1)+31+4(16)=98 amu.
1 mol (H₃PO₄)=98 g
1 mol= 6.022 * 10²³ molecules.
2) we calculate the mass of 4.00*10²³ molecules.
98 g6.022*10²³ molecules
x4.00*10²³ molecules
x=(98 g * 4.00*10²³ molecules) / 6.022*10²³ molecules≈65 g
65 g
Ответ: