Suppose that the microwave radiation has a wavelength of 12 cmcm . How many photons are required to heat 245 mLmL of coffee from 25.0 ∘C∘C to 62.0 ∘C∘C? Assume that the coffee has the same density, 0.997 g/mLg/mL , and specific heat capacity, 4.184 J/(g⋅K)J/(g⋅K) , as water over this temperature range.
Solved
Show answers
More tips
- S Style and Beauty Is Photoepilation the Solution to Unwanted Hair Forever?...
- O Other What is a Disk Emulsifier and How Does it Work?...
- F Family and Home What does a newborn need?...
- F Family and Home Choosing the Right Car Seat for Your Child: Tips and Recommendations...
- F Food and Cooking How to Get Reconfirmation of Registration?...
- C Computers and Internet How to Get Rid of Spam in ICQ?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
- F Family and Home How to Get Rid of Your Neighbors?...
- S Society and Politics How Could Nobody Know About the Dead Mountaineers?...
- H Health and Medicine How to Cure Adenoids?...
Answers on questions: Chemistry
- C Chemistry Explain how a light can be seen when sent through a colloid mixture, but not a solution. i have 5 minutes pls help...
- H History What do you call a chicken crossing the road....
- M Mathematics Jackson has 2,000 baseball cards in his collection. gave has 1/10 as many baseball cards in his collection as jackson. how many baseball cards does gave have in...
- E English When i was three and bailey four, we had arrived in the musty little town, wearing tags on our wrists which instructed – ‘to whom it may concern’ – that we were...
- E English What is a dna and what is the mean of dna and for what it works...
Ответ:
2.281*10^28 photons
Explanation:
Data
Volume of coffee, V = 245 mLTemperature change of the coffee, ΔT = 62 - 25 = 37 °C Density of coffee, D = 0.997 g/mLSpecific heat capacity of coffee, cp = 4.184 J/(g*K) = 4.184 J/(g* °C)wavelength of the microwave radiation, λ = 12 cm = 0.12 mMass of the coffee
m = D*V = 0.997 * 245 = 244.265 g
Energy (heat) absorbed by the coffee
Q = m*cp*ΔT = 244.265 * 4.184 * 37 = 37814.1761 J
Energy of the photon
E = h*c/λ
where h is the Planck constant ( 6.63 x 10^(-34) J*s) and c is the speed of light at vacuum (3*10^8 m/s)
E = 6.63 x 10^(-34)*3*10^8/0.12 = 1.6575*10^(-24) J
number of photons required = total energy required / energy per photon
n = 37814.1761/1.6575*10^(-24) = 2.281*10^28 photons
Ответ:
Antoine-Laurent Lavoisier forever changed the practice and concepts of chemistry by ... Combustion, he said, was the reaction of a metal or an organic substance with that part of ... She made many of the entries in his laboratory notebooks.
Explanation: