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tiffanibell71
22.09.2019 •
Chemistry
The activation energy for a given reaction is 56 kj/mol. at what temperature would the rate constant be quadruple what is was at 273k?
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Ответ:
The rate equation is given as:
k = A e^(- Ea / RT)
Dividing state 1 and state 2:
k1/k2 = e^(- Ea / RT1) / e^(- Ea / RT2)
k1/k2 = e^[- Ea / RT1 - (- Ea / RT2)]
k1/k2 = e^[- Ea / RT1 + Ea / RT2)]
Taking the ln of both sides:
ln (k1/k2) = - Ea / RT1 + Ea / RT2
ln (k1/k2) = - Ea / R (1/T1 - 1/T2)
Since k2 = 4k1, therefore k1/k2 = ¼
ln (1/4) = [- (56,000 J/mol) / (8.314 J / mol K)] (1/273 K – 1/ T2)
2.058 x 10^-4 = 1/273 – 1/T2
T2 = 289.25 K
Ответ:
it is true
Explanation:
"there are three noteworthy elements in the transition metals family such as the elements of iron like iron itself , nickel , and they are known to produce a magnetic field"