The aim of this exercise is to determine the percentage (degree) of acetic acid in vinegar.
For this purpose 10 mL of vinegar requires 8mL of sodium hydroxide of molar concentration
0.1mol/L to react with the acetic acid present.
The equation of the reaction is :
CH3COOH + OH- -> CH3COO- + H2O
a- Find the mass of acetic acid present in 10mL vinegar
b- Find the percentage of acetic acid in vinegar.
Given: M (CH3COOH) = 60 g/mol
Density of vinegar = 1.02g/mL
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Ответ:
Actual volume=Final volume-initial volume=40-30=10mL
Mass=5g