The compounds CH OH and CH COOH react in the presence of an acid catalyst to form:
a) a carboxylic acid
b) an aldehyde
c) a ketone
d) an ester
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Ответ:
The question is incomplete, the complete question is:
The solubility of slaked lime,
, in water is 0.185 g/100 ml. You will need to calculate the volume of 
M HCl needed to neutralize 14.5 mL of a saturated
The volume of HCl required is 290mL, the mass of
is 0.0268g, the moles of
Explanation:
Given values:
Solubility of
= 0.185 g/100 mL
Volume of
= 14.5 mL
Using unitary method:
In 100 mL, the mass of
present is 0.185 g
So, in 14.5mL. the mass of
present will be =
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
Given mass of
= 0.0268 g
Molar mass of
= 74 g/mol
Plugging values in equation 1:
Moles of
present = 
The chemical equation for the neutralization of calcium hydroxide and HCl follows:
By the stoichiometry of the reaction:
Moles of
= Moles of 
= 0.000724 mol
The formula used to calculate molarity:
Moles of HCl = 0.000724 mol
Molarity of HCl =
Putting values in equation 2, we get:
Hence, the volume of HCl required is 290mL, the mass of
is 0.0268g, the moles of