The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate (a) the lattice parameter; and (b) the atomic radius of potassium.
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Ответ:
For a: The edge length of the crystal is 533.5 pm
For b: The atomic radius of potassium is 231.01 pm
Explanation:
For a:To calculate the lattice parameter or edge length of the crystal, we use the equation:
where,
= density =
Z = number of atom in unit cell = 2 (BCC)
M = atomic mass of metal = 39.09 g/mol
= Avogadro's number =
a = edge length of unit cell = ?
Putting values in above equation, we get:
Conversion factor:
Hence, the edge length of the crystal is 533.5 pm
For b:To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:
where,
R = radius of the lattice = ?
a = edge length = 533.5 pm
Putting values in above equation, we get:
Hence, the atomic radius of potassium is 231.01 pm
Ответ:
15 feet by 12 feet or 10 feet by 18 feet
Step-by-step explanation: