The empirical formula of a gaseous fluorocarbon is cf2. at a certain temperature and pressure, a 1-l volume holds 8.93 g of this fluorocarbon, whereas under the same conditions, the 1-l volume holds only 1.70 g gaseous fluorine (f2). determine the molecular formula of this compound.

C₄F₈

Explanation:

Using their mole ratio to compute their mass

molar mass of carbon = 12.0107 g/mol

molar mass of fluorine gas = 37.99681

let x = mass of carbon

given mass of fluorine = 1.70 g

x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4

molecular formula of CF₂ = 4 (CF₂) = C₄F₈

A-paper, wood, cardboard, and most plastics
B-flammable or combustible liquids such as gasoline, kerosene, grease and oil
C-electrical equipment, such as appliances, wiring, circuit breakers and outlets
D-chemical stuff (like a lab) They are for fires that involve combustible metals, such as magnesium, titanium, potassium and sodium.
I believe there is a K too - involve cooking oils, trans-fats, or fats in cooking appliances and are typically found in restaurant and cafeteria kitchens.