Chemistry: The equilibrium constant K, for the reaction 2NO2 (g) = 2NO (g) + O2(g)is 158 at 1000 K. What is the equilibrium pressure of O, ifthe PNo: = 0.400 atm and PNo = 0.270 atm?

The equilibrium constant K, for the reaction

Ответ:

Blansery6819

09.11.2022

Chemistry

$\Delta H=-92.7kJ$

Explanation:

Hello there!

In this case, according to the given information, we can infer that 890 kJ of energy are released when 1 mole of methane is burned; however, to find the total heat when 1.67 grams are burned, we first need to calculate the moles in this mass of methane:

$1.67gCH_4*\frac{1molCH_4}{16.04gCH_4}=0.104molCH_4$

And thus, for calculating the resulting ∆H, we proceed as follows:

$\Delta H=-890kJ/mol*0.104mol\\\\\Delta H=-92.7kJ$

Regards!

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The equilibrium constant K, for the reaction 2NO2 (g) = 2NO (g) + O2(g)
is 158 at 1000 K. What is the equilibrium pressure of O, if
the PNo: = 0.400 atm and PNo = 0.270 atm?

Ответ:

Ответ:

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