The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol of Cl2 in a 1.00-L reaction vessel at 230°C, what is the concentration of PCl3 when equilibrium has been established?

Concentration of PCl₅ at equilibrium = 24.01 mole/lit

Explanation:

Given

    Equilibrium constant  Kc = 49

                      PCl₃ (g) + Cl₂(g) ⇄ PCl₅(g)

According to Law of Mass action

Given that

Concentration of PCl₃ = 0.7 mole/lit & conc. of Cl₂ = 0.7 mole/lit

∴ volume of the vessel constant = 1 lit

    ∴ Concentration of PCl₅ at equilibrium = 49 x 0.7 x 0.7 = 24.01

The correct answer is D, between sentence five and six

Explanation:

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