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lalalalal5
05.05.2020 •
Chemistry
The final solution had a volume of 1.0L and a molarity of 0.925. How many moles of Nickel (II) chloride were present in the solution?
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Ответ:
The moles of nickel (II) chloride were present in the solution are 0.925
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
where,
Molarity = 0.925
n= moles of solute = 0.2
Now put all the given values in the formula of molarity, we get
Therefore, the moles of nickel (II) chloride were present in the solution are 0.925
Ответ:
Im not entirely sure, but i think the answer is c was i right let me know.