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unknowntay04
07.04.2020 •
Chemistry
The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution containing the four anions, each at a concentration of 0.10 M, in what order would they precipitate?Compound:
a.AgCl ksp: 1.8x10^-10
b.Ag_2_CrO_4_ksp: 1.1 x 10 ^-12
c.AgBrksp: 5.4 x10 ^ -13
d.AgIksp: 8.5 x 10 ^ -17
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Ответ:
AgI, AgBr, AgCl and Ag₂CrO₄
Explanation:
Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:
XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)
Where X is cation and Y is anion.
Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ
The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. Where X is the solubility of the compound.
Replacing in Ksp:
Ksp = [ax]ᵃ [nx]ⁿ
Solving for x, Solubility (S) is defined as:
For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:
The lower solubility is the first compound in precipitate, thus, order of precipitation is:
AgI, AgBr, AgCl and Ag₂CrO₄
Ответ: