Chemistry: The following reaction produces ethanoic acid (chacooh) from methanol (ch3oh) and carbon monoxide chcooh ch3oh + co relative atomie mass: h = 1: 0 = 16; c = 12 calculate the maximum mass of ethanoic acid that can be produced from 160g methanol, assuming the carbon monoxide is in excess.

The following reaction produces ethanoic acid

Ответ:

itzjames025

02.01.2022

$\boxed{\text{300 g}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32 60

CH₃OH + CO ⟶ CH₃COOH

m/g: 160

(a) Moles of CH₃OH

$\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}$

(b) Moles of CH₃COOH

$\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}$

$\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}$

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The following reaction produces ethanoic acid (chacooh) from methanol (ch3oh) and carbon
monoxide
chcooh
ch3oh + co
relative atomie mass: h = 1: 0 = 16; c = 12
calculate the maximum mass of ethanoic acid that can be produced from 160g methanol,
assuming the carbon monoxide is in excess.

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